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(3/x2+3x-10)+(4/x2+x-6)= voy a aplicar el metodo del aspa simple
3/(x+5)(x-2)+4/(x+3)(x-2) saco minimo (x-2)(x+5)(x+3) divido con el denominador y multiplico con el numerador.
3(x+3) +4(x+5)/(x-2)(x+5)(x+3)
3x+9+4x+20/(x+2)(x+5)(x+3)
7x+29/(x+2)(x+5)(x+3)