Respuesta:
θ=2πn,θ=π+2πn
Operación paso a paso:
cos² ( θ ) + 2sin ( θ ) - 1= 0
sin ² ( θ ) + 2sin ( θ ) = 0
sin ( θ ) = 0, sin ( θ ) = 2
sin ( θ ) = 0 : θ=2πn, θ=π+2πn
sin ( θ ) = 2
θ = 2πn, θ= π + 2πn
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Respuesta:
θ=2πn,θ=π+2πn
Operación paso a paso:
cos² ( θ ) + 2sin ( θ ) - 1= 0
sin ² ( θ ) + 2sin ( θ ) = 0
sin ( θ ) = 0, sin ( θ ) = 2
sin ( θ ) = 0 : θ=2πn, θ=π+2πn
sin ( θ ) = 2
θ = 2πn, θ= π + 2πn