Respuesta:
Por Pitágoras:
[tex] {a}^{2} + \sqrt{3} {}^{2} = ( 2\sqrt{2}) {}^{2} \\ {a }^{2} + 3 = 8 \\ {a}^{2} = 5 \\ a = \sqrt{5} [/tex]
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Respuesta:
Por Pitágoras:
[tex] {a}^{2} + \sqrt{3} {}^{2} = ( 2\sqrt{2}) {}^{2} \\ {a }^{2} + 3 = 8 \\ {a}^{2} = 5 \\ a = \sqrt{5} [/tex]