Explicación paso a paso:
1.f(-3) = (-3)^{2} - 2(-3) -3f(−3)=(−3)
2
−2(−3)−3 => f(-3) = 12
f(-2) = (-2)^{2} - 2(-2) -3 => f(-2) = 5f(−2)=(−2)
−2(−2)−3=>f(−2)=5
f(-1) = (-1)^{2} -2(-1) - 3 => f(-1) = 0f(−1)=(−1)
−2(−1)−3=>f(−1)=0
f(0) = (0)^{2} -2(0) - 3 => f(0) = -3f(0)=(0)
−2(0)−3=>f(0)=−3
f(1) = (1)^{2} -2(1) - 3 => f(1) = -4f(1)=(1)
−2(1)−3=>f(1)=−4
f(2) = (2)^{2} -2(2) - 3 => f(2) = -3f(2)=(2)
−2(2)−3=>f(2)=−3
f(3) = (3)^{2} -2(3) - 3 => f(3) = 0f(3)=(3)
−2(3)−3=>f(3)=0
2.f(x) = – x2 + 5x – 6
0 = -4+5x
-5x=-4
x=4/5
espero que te ayude ^_^
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Explicación paso a paso:
1.f(-3) = (-3)^{2} - 2(-3) -3f(−3)=(−3)
2
−2(−3)−3 => f(-3) = 12
f(-2) = (-2)^{2} - 2(-2) -3 => f(-2) = 5f(−2)=(−2)
2
−2(−2)−3=>f(−2)=5
f(-1) = (-1)^{2} -2(-1) - 3 => f(-1) = 0f(−1)=(−1)
2
−2(−1)−3=>f(−1)=0
f(0) = (0)^{2} -2(0) - 3 => f(0) = -3f(0)=(0)
2
−2(0)−3=>f(0)=−3
f(1) = (1)^{2} -2(1) - 3 => f(1) = -4f(1)=(1)
2
−2(1)−3=>f(1)=−4
f(2) = (2)^{2} -2(2) - 3 => f(2) = -3f(2)=(2)
2
−2(2)−3=>f(2)=−3
f(3) = (3)^{2} -2(3) - 3 => f(3) = 0f(3)=(3)
2
−2(3)−3=>f(3)=0
2.f(x) = – x2 + 5x – 6
0 = -4+5x
-5x=-4
x=4/5
espero que te ayude ^_^