2a + 40° + 2a + a = 180°
5a + 40° = 180°
5a = 180° - 40°
5a = 140°
a = 140°/5
a = 28°
Eternamente
☆꧁☆༒ axllxa ༒☆꧂☆
La respuesta correcta es B) 28°
[tex]\bf{2\alpha + 40 + 2\alpha +\alpha = 180 } \\ \\ \bf{5\alpha + 40 = 180} \\ \\ \bf{5\alpha = 180 - 40} \\ \\ \bf{5\alpha = 140} \\ \\ \bf{\alpha = \frac{140}{5} } \\ \\ \large\boxed{\bf\red{\alpha = 28}}[/tex]
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2a + 40° + 2a + a = 180°
5a + 40° = 180°
5a = 180° - 40°
5a = 140°
a = 140°/5
a = 28°
Eternamente
☆꧁☆༒ axllxa ༒☆꧂☆
CALCULAR EL VALOR DE α (alfa)
La respuesta correcta es B) 28°
[tex]\bf{2\alpha + 40 + 2\alpha +\alpha = 180 } \\ \\ \bf{5\alpha + 40 = 180} \\ \\ \bf{5\alpha = 180 - 40} \\ \\ \bf{5\alpha = 140} \\ \\ \bf{\alpha = \frac{140}{5} } \\ \\ \large\boxed{\bf\red{\alpha = 28}}[/tex]