Respuesta:
TRIÁNGULO
PRIMERO HALLAMOS "H"
[tex] ({13})^{2} = ({5})^{2} + {h}^{2} \\ 169 = 25 + {h}^{2} \\ 169 - 25 = {h}^{2} \\ \sqrt{144} = h \\ 12 = h[/tex]
ÁREA DEL RECTÁNGULO
[tex]b \times h = 84 \\ x \times 12 = 48 \\ x = \frac{48}{12} \\ x = 4[/tex]
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Verified answer
Respuesta:
TRIÁNGULO
PRIMERO HALLAMOS "H"
[tex] ({13})^{2} = ({5})^{2} + {h}^{2} \\ 169 = 25 + {h}^{2} \\ 169 - 25 = {h}^{2} \\ \sqrt{144} = h \\ 12 = h[/tex]
ÁREA DEL RECTÁNGULO
[tex]b \times h = 84 \\ x \times 12 = 48 \\ x = \frac{48}{12} \\ x = 4[/tex]