Explicación paso a paso:
La suma o resta de fracciones es una de las operaciones básicas que permite combinar dos o más fracciones
[tex]\frac{2}{3} + \frac{5}{6}=\frac{(2)(2) + (5)(1) }{6} =\frac{4+5}{6} =\frac{9}{6} =\frac{3}{2} \\\\\frac{4}{3} + \frac{3}{8}=\frac{(4)(8) + (3)(3) }{24} =\frac{32+9}{24} =\frac{41}{24} \\\\\frac{3}{4} + \frac{1}{2}=\frac{(3)(1) + (1)(2) }{4} =\frac{3+2}{4} =\frac{5}{4}[/tex]
[tex]\frac{5}{6} - \frac{2}{3}=\frac{(5)(1) - (2)(2) }{6} =\frac{5-4}{6} =\frac{1}{6} \\\\\frac{7}{2} - \frac{9}{6}=\frac{(7)(3) - (9)(1) }{6} =\frac{21-9}{6} =\frac{12}{6} =2\\\\\frac{4}{6} - \frac{1}{3}=\frac{(4)(1) - (1)(2) }{6} =\frac{4-2}{6} =\frac{2}{6} =\frac{1}{3}[/tex]
Respuesta:
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Verified answer
Explicación paso a paso:
La suma o resta de fracciones es una de las operaciones básicas que permite combinar dos o más fracciones
[tex]\frac{2}{3} + \frac{5}{6}=\frac{(2)(2) + (5)(1) }{6} =\frac{4+5}{6} =\frac{9}{6} =\frac{3}{2} \\\\\frac{4}{3} + \frac{3}{8}=\frac{(4)(8) + (3)(3) }{24} =\frac{32+9}{24} =\frac{41}{24} \\\\\frac{3}{4} + \frac{1}{2}=\frac{(3)(1) + (1)(2) }{4} =\frac{3+2}{4} =\frac{5}{4}[/tex]
[tex]\frac{5}{6} - \frac{2}{3}=\frac{(5)(1) - (2)(2) }{6} =\frac{5-4}{6} =\frac{1}{6} \\\\\frac{7}{2} - \frac{9}{6}=\frac{(7)(3) - (9)(1) }{6} =\frac{21-9}{6} =\frac{12}{6} =2\\\\\frac{4}{6} - \frac{1}{3}=\frac{(4)(1) - (1)(2) }{6} =\frac{4-2}{6} =\frac{2}{6} =\frac{1}{3}[/tex]
Respuesta: