Respuesta:
[tex]\frac{3\sqrt{2y+40}}{2y+40}[/tex]
Explicación paso a paso:
[tex]\frac{3}{\sqrt{2y+40}}=\frac{3}{\sqrt{2y+40}}.\frac{\sqrt{2y+40}}{\sqrt{2y+40}}=\frac{3\sqrt{2y+40}}{\sqrt{2y+40}^{2}}=\frac{3\sqrt{2y+40}}{2y+40}[/tex]
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Respuesta:
[tex]\frac{3\sqrt{2y+40}}{2y+40}[/tex]
Explicación paso a paso:
[tex]\frac{3}{\sqrt{2y+40}}=\frac{3}{\sqrt{2y+40}}.\frac{\sqrt{2y+40}}{\sqrt{2y+40}}=\frac{3\sqrt{2y+40}}{\sqrt{2y+40}^{2}}=\frac{3\sqrt{2y+40}}{2y+40}[/tex]