Ayuda con la sgt identidad trigonotrica
cosB(cscB+TanB)=cotB+senB
cosB(cscB+TanB)=cotB+senB
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cosB(cscB + tanB) = cotB + senB (cscB = 1/senB , tanB = senB/cosB)
CosB(1/senB + senB/cosB) = cotB + senB
cosB((cosB + sen²B)/cosB. senB) = cotB + senB (Simplificas cosB)
(cosB + sen²B)/senB = cotB + senB
cosB/SenB + Sen²b/senB = cotB + senB (cosB/senB = cotB)
cotB + senB = cotB + senB