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-4x^4 - 4x³ + 16x² 4x² - x + 17
...................................................
0 x^4 - x³ + 16x² + mx
+ x³ + x² - 4x
........................................................
0x³ + 17x² + (mx- 4x) + n
- 17x² - 17x + 68
...................................................................
(mx-4x) -17x + (n+68)
Entonces el residuo es 2x - 5
(mx-4x) -17x + (n+68) = mx - 21x + (n+20)
Resolviendo cada coeficiente, tenemos que
Espero que te sirva, salu2!!!!