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1 + 2²(1² + 2² + 3² + 4² + 5² + 6² + 7² + 8²) =
1 + 4 [ (8)(8+1)(2(8)+1)]/6
1 + 4 [ (8)(9)(17) ]/6
1 + 4 [ 1224 ]/6
1 + 4 [ 204 ]
1 + 816.
817. RESPUESTA.
Recuerda que la suma de cuadrados es:
1²+2²+3²+...+n² = n(n+1)(2n+1)/6