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La altura de caída es h = 120 cm . sen60° = 104 cm
T = - (m g h - 0) = - 0,25 kg . 9,80 m/s² . 1,04 m = - 2,548 J
Si parte del reposo V = √(2 g h)
V = √(2 . 9,80 m/s² . 1,04 m) = 4,51 m/s
Saludos Herminio