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log ₂ x + log₂ (x+4) = 5 ; suma de logaritmos
log₂ [x(x+4)] = 5
Entonces
2^5 = x(x+4)
32 = x² ⁺ 4x ; buscamos un trinomio cuadrado perfecto
32 + 4 = x² + 2(x)(2) + 2²
36 = (x + 2)²
x + 2 = √36
x + 2 = 6 v x + 2 = -6
x = 4 v x = -8
Tenemos dos respuestas.