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Consideremos esto:
"A": alemanes y "i" italianos
4A, 5i
A) (4/9)(5/8)=5/18
B) (5/9)(4/8)=5/18
C) (4/9)(3/8) + (5/9)(4/8) = 3/18+5/18=8/18=4/9
D) (4/9)(5/8) =5/18
con reposicion
4A, 5i
A) (4/9)(5/9)=20/81
B) (5/9)(4/9)=20/81
C) (4/9)(3/9) + (5/9)(4/9) = 32/81
D) (4/9)(5/9) =20/81