Respuesta:
x² + 3x - 10 = 0
[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]\mathrm{Para\:}\quad a=1,\:b=3,\:c=-10[/tex]
[tex]x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-10\right)}}{2\cdot \:1}[/tex] [tex]\sqrt{3^2-4\cdot \:1\cdot \left(-10\right)}[/tex]
[tex]=\sqrt{3^2+4\cdot \:1\cdot \:10}[/tex]
[tex]=\sqrt{3^2+40}\\=\sqrt{9+40}\\=\sqrt{49}\\= 7[/tex]
[tex]x_1=\frac{-3+7}{2\cdot \:1},\:\\\\x_2=\frac{-3-7}{2\cdot \:1}[/tex]
[tex]\frac{-3+7}{2\cdot \:1}=\frac{4}{2\cdot \:1} =\frac{4}{2}=2[/tex]
[tex]\frac{-3-7}{2\cdot \:1}=\frac{-10}{2\cdot \:1}=\frac{-10}{2}=-5[/tex]
[tex]x=2,\:x=-5[/tex]
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Respuesta:
x² + 3x - 10 = 0
[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
[tex]\mathrm{Para\:}\quad a=1,\:b=3,\:c=-10[/tex]
[tex]x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-10\right)}}{2\cdot \:1}[/tex] [tex]\sqrt{3^2-4\cdot \:1\cdot \left(-10\right)}[/tex]
[tex]=\sqrt{3^2+4\cdot \:1\cdot \:10}[/tex]
[tex]=\sqrt{3^2+40}\\=\sqrt{9+40}\\=\sqrt{49}\\= 7[/tex]
[tex]x_1=\frac{-3+7}{2\cdot \:1},\:\\\\x_2=\frac{-3-7}{2\cdot \:1}[/tex]
[tex]\frac{-3+7}{2\cdot \:1}=\frac{4}{2\cdot \:1} =\frac{4}{2}=2[/tex]
[tex]\frac{-3-7}{2\cdot \:1}=\frac{-10}{2\cdot \:1}=\frac{-10}{2}=-5[/tex]
[tex]x=2,\:x=-5[/tex]