June 2023 1 12 Report
Ayuda alguien me puede ayudar?:(
Nombre UIQPA
NaOH
AuOH
Au(OH)3
AgOH
Be(OH)2
Daré coronita;)
Si respondes algo que no reporto:(

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.