Ayuda a resolver lo siguiente:
(3x²+3x-5)+(7x+x²)+(8-4x+6x²)=¿?
(3x²+2xy-7)+(7x²-4xy+8)=¿?
2a²bc³-5a²bc³+3a²bc³-2a²bc³=¿?
2x²y3z+3x²y³z=¿?
(4x+3y-8z)+(7x-8y+5z)=¿?
(4x³+5x-7x²-9)-(6x³-4x+3x²-3)=¿?
Gracias
(3x²+3x-5)+(7x+x²)+(8-4x+6x²)=¿?
(3x²+2xy-7)+(7x²-4xy+8)=¿?
2a²bc³-5a²bc³+3a²bc³-2a²bc³=¿?
2x²y3z+3x²y³z=¿?
(4x+3y-8z)+(7x-8y+5z)=¿?
(4x³+5x-7x²-9)-(6x³-4x+3x²-3)=¿?
Gracias
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(3x²+2xy-7)+(7x²-4xy+8)= 10x² - 2xy + 1
2a²bc³-5a²bc³+3a²bc³-2a²bc³ = -2a²bc³
2x²y3z+3x²y³z= 2x²y3z + 3x²y³z
(4x+3y-8z)+(7x-8y+5z)= 11x-5y-3z
(4x³+5x-7x²-9)-(6x³-4x+3x²-3)= -2x³ + 9x -10x² -6