x + (x+1)+ (x+2) + (x+3) = 194
4x+6= 194
x= (194-6)/4
x= 47
por lo tanto 47 + (47+1) +(47+2) +(47+3) = 194
los números consecutivos son: 47, 48, 49 y 50
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x + (x+1)+ (x+2) + (x+3) = 194
4x+6= 194
x= (194-6)/4
x= 47
por lo tanto 47 + (47+1) +(47+2) +(47+3) = 194
los números consecutivos son: 47, 48, 49 y 50