H+ = ka [AL]/[Bs kj]
= 10^-5 x 0,2/0,02
= 10^-6
pH = - log 10^-6
= 6
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H+ = ka [AL]/[Bs kj]
= 10^-5 x 0,2/0,02
= 10^-6
pH = - log 10^-6
= 6