Arus sebesar 0,25 ampere mengalir selama 2 menit. Jika energi yang timbul 180 joule. tentukan:
a.muatannya
b.beda potensialnya
a.muatannya
b.beda potensialnya
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t = 2 menit = 120 s
W = 180 J
a. q = I. t
= 0,25 . 120 s
= 30 C
b. V = w/q
= 180 / 30
= 6 volt