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y = triciclo
x+y = 7
2x+3y = 17
despejas la primera
x = 7-y
reemplazas en la segunda
14-2y+3y = 17
14+y = 17
y = 17-14 = 3
hallas x
x + 3 = 7
x = 4
entonces hay 4 bicicletas y 3 triciclos