Respuesta:
A) 20
Explicación paso a paso:
x = 3k → 3(2) = 6
y = 5k → 5(2) = 10
z = 2k → 2(2) = 4
(3k)² + (5k)² + (2k)² = 152
9k² + 25k² + 4k² = 152
38k² = 152
k² = 4
k = 2
x + y + z = 6 + 10 + 4
x + y + z = 20
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Respuesta:
A) 20
Explicación paso a paso:
x = 3k → 3(2) = 6
y = 5k → 5(2) = 10
z = 2k → 2(2) = 4
(3k)² + (5k)² + (2k)² = 152
9k² + 25k² + 4k² = 152
38k² = 152
k² = 4
k = 2
x + y + z = 6 + 10 + 4
x + y + z = 20