Jawab:
f(0)=(a.0 +b) / (0^2+1)
f(0)=b
f(x)=(ax+b)/(x^2+1)
u=ax+b
u'=a
v=x^2+1
v'=2x
f'(x) =(u'*v-u*v') /v^2
f'(x) =[(a)(x^2+1)-(ax+b)(2x) ]/(x^2+1)^2
f'(0)=[(a) (0+1)-(a.0+b)(2(0)]/(0+1)^2
f'(0)=a
f(0)=f'(0)
b=a
jika f'(-1)=1
maka
f'(-1)=[(a)(1+1)-(a(-1)+b)(2(-1))]/(1+1)^2
1=(2a+2(-a+b))/4
1*4=2a-2a+2b
4=2b
4/2=b
2=b
karna a=b=2
maka a + b = 2+2=4
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Jawab:
f(0)=(a.0 +b) / (0^2+1)
f(0)=b
f(x)=(ax+b)/(x^2+1)
u=ax+b
u'=a
v=x^2+1
v'=2x
f'(x) =(u'*v-u*v') /v^2
f'(x) =[(a)(x^2+1)-(ax+b)(2x) ]/(x^2+1)^2
f'(0)=[(a) (0+1)-(a.0+b)(2(0)]/(0+1)^2
f'(0)=a
f(0)=f'(0)
b=a
jika f'(-1)=1
maka
f'(-1)=[(a)(1+1)-(a(-1)+b)(2(-1))]/(1+1)^2
1=(2a+2(-a+b))/4
1*4=2a-2a+2b
4=2b
4/2=b
2=b
karna a=b=2
maka a + b = 2+2=4