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f(x) = (x + 1)(x - 3)H(x) + 5x - 4
f(x) = (x - 3)(x - 5)H(x) + (ax + b)
faktor (x - 3):
f(3) = 5(3) - 4 = 11
faktor (x - 5):
f(5) = 3(5) + 2 = 17
eliminasi:
3a + b = 11
5a + b = 17
__________ -
- 2a = - 6
a = 3
b = 2
sisanya: 3x + 2