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Verified answer
Jawab⁷log 2. ²log 3 = a b
⁷log 3 = ab
²⁴log 98 = ⁷log 98/⁷log 24
= (⁷log 49(2)) /(⁷log 8(3))
= (⁷log 7² + ⁷log 2) / (⁷log 2³ + ⁷log 3)
= (2 + a) /(3a + ab)