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t = 1 m → 10 dm
Volume yang ditambahkan = ( ¹/₄ πd² t ) - 40 liter
= ( ¹/₄ x ²²/₇ x 7 x 7 x 10 ) - ( 40 liter x 1 )
= ( ¹/₄ x 22 x 70 ) - 40 dm³
= 385 dm³ - 40 dm³
= 345 dm³