Alkohol o masie cząsteczkowej 116
M =116 u
Wzór ogólny alkoholi:
CnH2n+1OH
12n+2n+1+16+1=116
14n=116-1-16-1
14n=116-18
14n=98 /:14
n=7
C7H15OH -ten alkohol to heptanol
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M =116 u
Wzór ogólny alkoholi:
CnH2n+1OH
12n+2n+1+16+1=116
14n=116-1-16-1
14n=116-18
14n=98 /:14
n=7
C7H15OH -ten alkohol to heptanol