Question

Aljabar,SEDERHANAKAN: 1.7(a+2b-3c)-3(2a-3b-2c)=
2. 2(3 × y- y ) - (4× y +y)=
3. (4p+2q-r)-(3p-4q-7r)=
4.2(3a² - 5a + 1 )-4(2a² - 6a -10 ) =

Answer 1

1. 7(a +2b -3c) -3(2a -3b -2c) 
   = 7a +14b -21c -6a +9b +6c
   = 7a -6a +14b +9b -21c +6c
   = a +23b -15c
2. 2(3xy -y) -(4xy +y)
   = 6xy -2y -4xy -y
   = 6xy -4xy -2y -y
   = 4xy -3y
3. (4p +2q -r) -(3p -4q -7r)
     = 4p +2q -r -3p +4q +7r
     = 4p -3p +2q +4q -r +7r
     = p +6q +6r
4. 2(3a² -5a +1) -4(2a² -6a -10)
   = 6a² -10a +2 -8a² +24a +40
   = 6a² -8a² -10a +24a +2 +40
   = -2a² +14a +42

Itu jawabannya.