A)
[tex]3.(2-x)+1=x-5-2x\\6-3x+1=-x-5\\7-3x=-x-5\\-3x+x=-5-7\\-2x=-12\\x=-(-\frac{12}{2})\\x=6[/tex]
B)
[tex]2.(4x-1)+4=2.7\\8x-2+4=14\\8x+2=14\\8x=14-2\\8x=12\\x=\frac{12}{8}\\\\x=\frac{3}{2}[/tex]
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A)
[tex]3.(2-x)+1=x-5-2x\\6-3x+1=-x-5\\7-3x=-x-5\\-3x+x=-5-7\\-2x=-12\\x=-(-\frac{12}{2})\\x=6[/tex]
B)
[tex]2.(4x-1)+4=2.7\\8x-2+4=14\\8x+2=14\\8x=14-2\\8x=12\\x=\frac{12}{8}\\\\x=\frac{3}{2}[/tex]