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Como las bases son diferentes, debemos aplicar logaritmos
(2x - 5)log3 =(x - 3)log2
(2x - 5)/(x - 3) = log2/log3
= (0,3010)/(0,4771)
= 0,6309
2x - 5 = (0,6309)(x - 3)
= 0,6309x - 1,8927
2x - 0,6309x = - 1,8927 + 5
1,3691x = 3,1073
x = (3,1073)/(1,3691)
x = 2,2700