Question

Alguien que me ayude

Answer 1

{[(x^4)^5•(x^2)^3]^2}/{[(x^-7)^2•x^8]^2}
[(x^20•x^6)^2]/[(x^-14•x^8)^2]
(x^40•x^12)/(x^-28•x^16)
x^52/x^-12
x^64

6+4=10
la c