Respuesta:
d)
Explicación:
K2CO3=39(2)+12+16(3)=78+12+48=138 gr/mol
[tex]m = 4mol(138 \frac{gr}{mol} ) = 552 \: gr[/tex]
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Respuesta:
d)
Explicación:
K2CO3=39(2)+12+16(3)=78+12+48=138 gr/mol
[tex]m = 4mol(138 \frac{gr}{mol} ) = 552 \: gr[/tex]