Question

Alguien que me ayude :c

Answer 1

A.

C: 47.35 g / 12 g/mol = 3.945 mol

H: 10.6 g / 1 g/mol = 10.6 mol

O: 42.05 g / 16 g/mol = 2.628 mol

Dividir

C: 3.945 mol / 2.628 mol = 1.5 x 2 = 3

H:  10.6 mol / 2.628 mol = 4 x 2 = 8

O: 2.628 mol / 2.628 mol = 1 x 2 = 2

Multiplica r todos los 2 ya que hay un resultado con 1,5

FE: C3H8O2

B)  C= 85 g/ 12 g/mol = 7.083 mol
       H = 14.3 g  / 1 g/mol = 14.3 mol
dividir

C: 7.083mol / 7.083 mol = 1
H= 14.3 mol / 7.083 mol = 2

FE = CH2

C)

C: 43.37 g / 12 g/mol = 3.614 mol

H: 10.59 g / 1 g/mol = 10.59 mol

O: 46.04 g / 16 g/mol = 2.878 mol

Dividir

C: 3.614 mol / 2.878 mol = 1

H:  10.59 mol / 2.878 mol = 4

O: 2.878 mol / 2.878 mol = 1

FE: CHO

D.

K: 26 g/ 39 g/mol = 0.666 mol

Cr: 35.4 g/ 52 g/mol = 0.680 mol

O: 38.02 g/ 16 g/mol = 2.378 mol

dividir

K: 0.666 mol / 0.666 mol= 1

Cr= 0.680 mol / 0.666 mol = 1

O= 2.378 mol / 0.666 mol = 4

FE= KCrO4

31.
A) 
C: 40 g/12 g/mol = 3.333 mol
H: 6.7 g/ 1 g/mol = 6.7 mol
O: 53.3 g / 16 g/mol = 3.331
dividir
C: 3.333 mol / 3.331 = 1
H: 3.7 mol / 3.331 mol = 1
O: 3.331 mol / 3.331 mol = 1
FE: CHO
Mn DE LA FE
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
O: 1 x 16 = 16 g/mol
````````````````````````````
       Mm = 29 g/mol
n = 60 g/mol / 29 g/mol = 2

FM = (CHO)n = (CHO)2 = C2H2O2

B.

C: 56.8 g/12 g/mol = 4.733mol
H: 6.5 g/ 1 g/mol = 6.5 mol
O: 28.4 g / 16 g/mol = 1.775 mol

N: 8.28 g/ 14 g/mol = 0.591 mol

dividir
C: 4.733 mol / 0.591 = 8
H: 6.5 mol / 0.591 mol = 11
O: 1.775 mol / 0.591 mol = 3

N: 0.591 mol / 0.591 mol = 1
FE: C8H11O3N
Mn DE LA FE
C: 8 x 12 = 96 g/mol
H: 11 x 1 = 11 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````
       Mm = 155 g/mol

n = 145 g/mol / 155 g/mol = 1

FM = (C8H11O3N)1 =C8H11O3N

C.
FE = C4H7
Mm FE
C:  4 x 12 = 48 g/mol
H: 7 x 1 = 7 g/mol
````````````````````````````
         Mm = 55 g/mol

n= 165 g/mol / 55 g/mol = 3

FM = (C4H7)3 = C12H21