Respuesta:
[tex] x_{1}=4 [/tex]
[tex] x_{2}=-1 [/tex]
Explicación paso a paso:
[tex]x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2a}[/tex]
[tex]a = 1 ,\:b = - 3, \: c = - 4[/tex]
[tex]x=\frac{-( - 3) \pm \sqrt{( - 3)^{2}-4(1)( - 4)}}{2(1)} \\ x=\frac{3 \pm \sqrt{9 + 16}}{2} \\ x=\frac{3\pm \sqrt{25}}{2} \\ x=\frac{3 \pm 5}{2}[/tex]
[tex] x_{1}=\frac{3+5}{2}=\frac{8}{2}=4 [/tex]
[tex] x_{2}=\frac{3-5}{2}=-\frac{2}{2}=-1 [/tex]
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Verified answer
Respuesta:
[tex] x_{1}=4 [/tex]
[tex] x_{2}=-1 [/tex]
Explicación paso a paso:
[tex]x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2a}[/tex]
[tex]a = 1 ,\:b = - 3, \: c = - 4[/tex]
[tex]x=\frac{-( - 3) \pm \sqrt{( - 3)^{2}-4(1)( - 4)}}{2(1)} \\ x=\frac{3 \pm \sqrt{9 + 16}}{2} \\ x=\frac{3\pm \sqrt{25}}{2} \\ x=\frac{3 \pm 5}{2}[/tex]
[tex] x_{1}=\frac{3+5}{2}=\frac{8}{2}=4 [/tex]
[tex] x_{2}=\frac{3-5}{2}=-\frac{2}{2}=-1 [/tex]