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= (3a) ( x + y) ( x² - xy + y²)
...............Kd
3ax³ + 3ay³ = Sacas factor comun 3a
3a(x³ + y³) = En el parentesis aplicas sumas de cubos
3a(x + y)(x² - xy + y²)
Respuesta.
3a(x + y)(a² - xy + y²)