Respuesta:
[tex](x \: \: \: y) = punto \: medio \: de \: la \: recta \\ ( \frac{x1 + x2}{2} \: \: \: \frac{y1 + y2}{2} ) = ( \frac{10 + ( - 8)}{2} \: \: \: \frac{1 2 + ( - 2)}{2} ) = (1 \: \: \: 5) [/tex]
[tex]q = \frac{x + y}{x - y} = \frac{1 + 5}{1 - 5} = \frac{6}{ - 4} = - \frac{3}{2} [/tex]
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Verified answer
Respuesta:
[tex](x \: \: \: y) = punto \: medio \: de \: la \: recta \\ ( \frac{x1 + x2}{2} \: \: \: \frac{y1 + y2}{2} ) = ( \frac{10 + ( - 8)}{2} \: \: \: \frac{1 2 + ( - 2)}{2} ) = (1 \: \: \: 5) [/tex]
[tex]q = \frac{x + y}{x - y} = \frac{1 + 5}{1 - 5} = \frac{6}{ - 4} = - \frac{3}{2} [/tex]