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◾ Materi : Listrik◾ Sub materi : Energi Listrk
◾ Mapel : Fisika
◾ Keyword : Energi Listrik, Listrik, Panas Listrik
Diketahui :
V = 220 volt
i = 500 mA = 0,5 A
t = 10 sekon
Ditanya :
W = ?
Penyelesaian :
W = Vit
W = (220)(0,5)(10)
W = 1100 J
Jadi, besarnya energi listrik alat pemanas tsb adalah 1100 J
Jawaban : C
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