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gr = 0.1 kg
c = 4200 Joule/kg°C
ΔT=T2 - 25°C
Dit:
T2=..?
Jawab:
I²Rt = mcΔT
0.25 * 100 * 60 = 0.1 * 4200 * (T2 - 25)
1500 = 420 (T2 - 25)
T2-25=3.58
T2=28.58°C