Respuesta:
(a - 5)/(2(a - 1))
Explicación paso a paso:
[tex]\mathrm{Simplificar} \\\\\\ \displaystyle = \frac{a^3-25a}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a^2-25)}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a+5)(a-5)}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a+5)(a-5)}{2a(a^2+4a-5)} \\\\\\ = \frac{a(a+5)(a-5)}{2a(a-1)(a+5)} \\\\\\ = \frac{(a+5)(a-5)}{(2(a+1))(a+5)} \\\\\\ = \boxed{ \frac{a-5}{2(a-1)} }[/tex]
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Respuesta:
(a - 5)/(2(a - 1))
Explicación paso a paso:
[tex]\mathrm{Simplificar} \\\\\\ \displaystyle = \frac{a^3-25a}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a^2-25)}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a+5)(a-5)}{2a^3+8a^2-10a} \\\\\\ = \frac{a(a+5)(a-5)}{2a(a^2+4a-5)} \\\\\\ = \frac{a(a+5)(a-5)}{2a(a-1)(a+5)} \\\\\\ = \frac{(a+5)(a-5)}{(2(a+1))(a+5)} \\\\\\ = \boxed{ \frac{a-5}{2(a-1)} }[/tex]