Explicación paso a paso:
(a+1)x2+ax+b<0; a<b
X=-a±raíz (a2-4*(a+1)*b))/2*(a+1)=
=-a±=raíz (a2-(4a+4)*b)/2a+2=
=-a±=raiz (a2-(4ab+4b))/2a+2=
=-a±raíz (a2-4ab-4b)/2a+2=
=-a±raíz (a2-4b(a+1))/2a+2
a2-4b(a+1)>=0
2a+2, cuando a=-1 no es solucion
Solución C) (-7, -1)
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Verified answer
Explicación paso a paso:
(a+1)x2+ax+b<0; a<b
X=-a±raíz (a2-4*(a+1)*b))/2*(a+1)=
=-a±=raíz (a2-(4a+4)*b)/2a+2=
=-a±=raiz (a2-(4ab+4b))/2a+2=
=-a±raíz (a2-4ab-4b)/2a+2=
=-a±raíz (a2-4b(a+1))/2a+2
a2-4b(a+1)>=0
2a+2, cuando a=-1 no es solucion
Solución C) (-7, -1)