Question

Aku post lagi ya no 4 karna kurang jelas:)

Answer 1

4. kalor A ke B : Q= mcΔT(0-ΔT-es) => 50×0.5×(0-(-5)=  25×5= 125 kalori
kalor B ke C : Q= mL => 50×80= 4000 kalori
kalor C ke D : Q= mcΔT(ΔT-air-0) => 50×1×(60-0)= 50×60= 3000 kalori
jadi, kalor C ke D 3000 kalori

Answer 2

Q=M.C.ΔT
M=50 gram
C air=1 kal gram 'c
ΔT=60'-0'=60'
Q=50.1.60=3000 kalori=B