akar persamaan kuadrat
1).4x²-4×-15=0
2). 6ײ+17×+12=0
bantuu pake cara makasihh
1).4x²-4×-15=0
2). 6ײ+17×+12=0
bantuu pake cara makasihh
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Penjelasan dengan langkah-langkah:
1. 4x² - 4x - 15 = 0
4x² + 6x - 10x - 15 = 0
2x(2x + 3) - 5(2x + 3)= 0
(2x - 5)(2x + 3)= 0
x1 = 5/2 atau x2 = -3/2
.
2). 6x² + 17x + 12 = 0
6x² + 9x + 8x + 12 = 0
3x(2x + 3) + 4(2x + 3)= 0
(3x + 4)(2x + 3)= 0
x1 = -4/3 atau x2 = -3/2