Question

Akar persamaan kuadrat x^{2} + 4x -12 =0 adalah?

Answer 1

x(x-2) + 6 (x -2)
(x-2) ( x + 6)
x - 2 = 0
x = 2

x + 6 = 0
x = -6

Answer 2

X²+4x-12 = 0
(x-2)(x+6) =0

x-2 =0
x = 2

x+6=0
x = -6

jadi persamaan akarnya adalah 2 dan -6