Question

Akar persamaan kuadrat X² + (P+1) X+8 =0 adalah A dan B. jika A = ½ B dan A B Positif maka nilai P adalah...

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Answer 1

Verified answer

PerSamaAn KuaDraT

x² + (p + 1)x + 8 = 0
a = 1
b = p + 1
c = 8

A × B = c/a = 8
1/2 B × B = 8
B² = 2 × 8
B = √16
B = 4 --> A dan B (+)

A = 1/2 B = 1/2 . 4 = 2

A + B = -b/a = -(p + 1)
4 + 2 = -p - 1
6 + 1 = -p
p = -7