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p.q= 5
p = p+2 , q= q+2
mencari akar-akar baru:
p+q = p+2 + q+3
=p+q+5
= 2+5 =7
p.q= (p+2) (q+2)
= p.q + 2p +2q +4
= p.q + 2 (p+q) + 4
= 5 + 2 (2) + 4 = 13
⇒ Persamaan kuadrat baru
x² - (p+q)x + pq
x² -7x +13
sorry kalo salah