Question

[(akar 3+2)^2-(akar 5+akar 2)^2] (akar 10+2 akar 3=

Answer 1

[(√3+2)²-(√5+√2)²] (√10+2 √3)
= [(√3²+2√3+2√3+2²)-(√5²+√5√2+√2√5+√2²)] (√10+2 √3)
= [(3+4√3+4)-(5+2√10+2)] (√10+2 √3)
=(3+4√3+4-5-2√10-2)(√10+2 √3)
=(4√3-2√10)(√10+2√3)
=4√3√10+4√3 2√3-2√10√10-2√10 2√3
=4√30+24-20-4√30
=4