Hasil dari 3(akar 6 + akar 2) / akar 3 - 1 adalah.... Question from @AStevenT512

December 2018 2 18 Report

Hasil dari 3(akar 6 + akar 2) / akar 3 - 1 adalah....

fahmilocked9 $\frac{3 (\sqrt6 + \sqrt2)}{\sqrt3-1} = \frac{3 (\sqrt2 \sqrt3 + \sqrt2)}{\sqrt3-1} \times \frac{\sqrt3 + 1}{\sqrt3 + 1} = \frac{3\sqrt2(\sqrt3+1)(\sqrt3+1)}{3-1} = \frac{3\sqrt2(\sqrt3+1)^2}{2}$

$\frac{3\sqrt2(3+2\sqrt3+1)}{2} = \frac{3\sqrt2(4+2\sqrt3)}{2} = \frac {12\sqrt2+6\sqrt6}{2} = \frac{12\sqrt2}{2} + \frac{6\sqrt6}{2} = 6 \sqrt2 + 3 \sqrt6$

$CMIIW$

0 votes Thanks 1

Shiqo 3(√6 + √2)/(√3 - 1) = 3(√2)(√3 + 1)/(√3 - 1)
= (3√2)(√3 + 1)/(√3 - 1) × (√3 + 1)/(√3 + 1)
= (3√2)(√3 + 1)²/(3 - 1)
= (3√2)(4 + 2√3)/(2)
= (3√2)(2 + √3)
= 6√2 + 3√6

Terimakasih smeoga membantu

0 votes Thanks 0

About Us

Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Bagaimana hubungan antara sistem pola hunian manusia praaksara dengan pola hunian masa kini?

F(x) =2x dan g(x) =sin x

Yg jago mandarin, ada yg bs ksh tau gk ini apa? bwt ujian bsk, mohon dg sangat, pls djwb. Thx

Bantuin yg ini jg ya. Yg dibuletin + caranya. Thx

Tlg bgt bantu no. 7-10 ya. Thx

Tolong jawab no. 9-10, thx

Jika x dan y memenuhi persamaan 2^4x-7y-7 = 4^x + 3y dan 27^x-y = 3^2x-7 maka y-x =

Recommend Questions

Life Enjoy

Get in touch

Social