Respuesta:
[tex] \frac{a}{3} + 1 = 19 \\ a + 1 = 19 \ \times 3 \\ a + 1 = 57 \\ a = 57 - 1 \\ a = 56 \\ \\ \frac{2m}{3} - 5 = 3 \\ 2m - 5 = \frac{3}{3} \\ 2m - 5 = 1 \\ 2m = 1 - 5 \\ 2m = - 4 \\ m = - \frac{4}{2} \\ m = - 2 \\ \\ \frac{2x - 1}{3} = 7 \\ 2x - 1 = 7 \times 3 \\ 2x - 1 = 21 \\ 2 x = 21 - 1 \\ 2x = 20 \\ x = \frac{20}{2 } \\ x = 10[/tex]
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Respuesta:
[tex] \frac{a}{3} + 1 = 19 \\ a + 1 = 19 \ \times 3 \\ a + 1 = 57 \\ a = 57 - 1 \\ a = 56 \\ \\ \frac{2m}{3} - 5 = 3 \\ 2m - 5 = \frac{3}{3} \\ 2m - 5 = 1 \\ 2m = 1 - 5 \\ 2m = - 4 \\ m = - \frac{4}{2} \\ m = - 2 \\ \\ \frac{2x - 1}{3} = 7 \\ 2x - 1 = 7 \times 3 \\ 2x - 1 = 21 \\ 2 x = 21 - 1 \\ 2x = 20 \\ x = \frac{20}{2 } \\ x = 10[/tex]