ぉしえんとのせばygらしあjjjjjjjjj
Respuesta:
[tex]\frac{(9^{-n})^{5} .(9^{6})^{n} .(9^{7})^{n} }{(9^{3})n^{2} .(9^{n} )^{5} } =\frac{9^{-5n} .9^{6n}.9^{7n} }{9^{3n} .9^{5n} } =\frac{9^{-5n+6n+7n} }{9^{3n+5n} } =\frac{9^{8n} }{9^{8n} } =1[/tex]
Rpta: sale 1
Explicación paso a paso:
Espero que te ayude :)
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ぉしえんとのせばygらしあjjjjjjjjj
Verified answer
Respuesta:
♫HOLA♫
[tex]\frac{(9^{-n})^{5} .(9^{6})^{n} .(9^{7})^{n} }{(9^{3})n^{2} .(9^{n} )^{5} } =\frac{9^{-5n} .9^{6n}.9^{7n} }{9^{3n} .9^{5n} } =\frac{9^{-5n+6n+7n} }{9^{3n+5n} } =\frac{9^{8n} }{9^{8n} } =1[/tex]
Rpta: sale 1
Explicación paso a paso:
Espero que te ayude :)