Question

Air sebanyak 200 gram bersuhu 90 derajat Celcius dicampur dengan air sebanyak 100 gram bersuhu 27 derajat celcius

Answer 1

Q lepas = Q terima
m . c . ΔT = m . c . ΔT
m . ΔT = m . ΔT
200 . (90 - T) = 100 . (T - 27)
2 (90 - T) = T - 27
180 - 2T = T - 27
180 + 27 = 3T
207 = 3T
69°C = T